Steam enters a turbine operating at steady state at 6 mpa, 600°c with a mass flow rate 125 kg/min and exits as a saturated vapor at 20 kpa. the turbine produces energy at a rate of 2 mw. kinetic and potential energy effects are negligible. the rate of heat loss from the turbine occurs to the air around the turbine at 27°c. a. what is the rate of entropy production for within the turbine? b. what is the isentropic efficiency of the turbine?
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Ответ:
The rate of entropy production for within the turbine is 0.441 kJ/kgK
The Isentropic efficiency of the turbine is 80.76%
Explanation:
Given:
Isentrophic properties of stream
=7.17Kj/kgK
Entropy generation of the stream:
=>![S_{g e n, c v}=\frac{\dot{S}_{g e n}}{\dot{m}}](/tpl/images/0434/0739/306cb.png)
=>
=>![\frac{\frac{W_{c v}}{\dot{m}}+\left(h_{2}-h_{1}\right)}{T_{b}}+\left(s_{2}- s_{1}\right)](/tpl/images/0434/0739/82744.png)
=>![\frac{\frac{2000}{2.083}+(2610-3660)}{300 K}+(7.91-7.17)](/tpl/images/0434/0739/a8db9.png)
=>![\frac{960.153+(-1050)}{300 K}+(0.74)](/tpl/images/0434/0739/432b7.png)
=>![\frac{-89.847}{300 K}+(0.74)](/tpl/images/0434/0739/698b5.png)
=> -0.299+(0.74)
=>0.441 kJ/kgK
Isentrophic efficeny of the turbine
=>![\eta=\frac{h_{1}-h_{2}}{h_{1}-h_{2 s}}](/tpl/images/0434/0739/4f201.png)
=>![\frac{3660-2610}{3660-2360}](/tpl/images/0434/0739/f4646.png)
=>![\frac{1050}{1300}](/tpl/images/0434/0739/a0261.png)
=>0.8076
=>80.76%
Ответ:
1.6 g
Explanation:
Use the formula: W = m× g
∴ g = W / m
Here, W = 128N
m = 80 Kg
∴ g = 128 ÷ 80
= 1.6 N (Ans)