Physics: Superman is standing 393 m horizontally away from lois lane. a villain drops a rock from 4.00 m directly above lois. if superman is to intervene and catch the rock just before it hits lois, what should be his minimum constant acceleration? if the acceleration is toward lois, enter a positive value. if the acceleration is away from lois, enter a negative value.

Superman is standing 393 m horizontally away from

Ответ:

jchavez5601

07.01.2022

Physics

-963.93 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$s=ut+\frac{1}{2}at^2\\\Rightarrow 4=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4\times 2}{9.81}}\\\Rightarrow t=0.903\ s$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 393=0\times 0.0903+\frac{1}{2}\times a\times 0.903^2\\\Rightarrow a=\frac{393\times 2}{0.903^2}\\\Rightarrow a=963.93\ m/s^2$

The acceleration of Superman would be -963.93 m/s² from Lois' perspective

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Ответ:

beluvangel418

19.09.2021

Physics

the answer is d. 12 protons and no electrons

Explanation:

For Mg atom the atomic number, Z=12

Number of protons in the nucleus = Atomic number of an atom =12

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