Suppose that 10 moles of an ideal gas have a gauge pressure of 2 atm and a temperature of 200 k. if the volume of the gas is doubled and the pressure dropped to a gauge pressure of 1 atm, what is the new temperature?
select one:

a.

267 k

b.

300 k

c.

400 k

d.

200 k

To solve this problem we will apply the concepts related to the equations of ideal gas, from there, we will define the proportion of these values between two states of matter. The ideal gas equation is defined as

Here,

P = Pressure

V = Volume

n = Amount of mass

R = Gas ideal constant

T = Temperature

Between two states we have,

The pressure at each state is,

According to the statement,

Then replacing,

Therefore the correct answer is A.

I only have the answer for A, but still, the answer is 20.07.

Explanation: Because the number ends in a 15, round to the nearest tenth which is 20. So now the number is 5420. To get the Watts (W) you have to take 5420 and divide it by the time in seconds. 4.5 minutes in seconds is 270, so 5420 divided by 270 equals 20.07. So 20.07 is the answer.