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beepbeep123
24.09.2020 •
Physics
Suppose you now take the ball and using a bat, pop it straight up into the air with a hang-time of 5.00 s (the hang time is how long the baseball is in the air after it leaves the bat). Determine the height to which the ball rises before it reaches its peak.
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Ответ:
Explanation:
Using the equation of motion formula
where;
S is the height to which the ball rises
u is the initial velocity of the ball = 0m/s
a is the acceleration due to gravity = 9.81m/s²
t is the time taken by the ball in air = 5.0s
Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s
Substituting the given parameters into the formula above to get S:
This means that the ball rises 30.66m before it reaches its peak.
Ответ:
Step-by-step explanation:
Equation of a circle is given as :
Take the derivative of the above with respect to x
The equation of the tangent is given by :