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SallyMarquez1201
27.08.2019 •
Physics
The acceleration of a particle is defined by the relation a 5 28 m/s2. knowing that x 5 20 m when t 5 4 s and that x 5 4 m when v 5 16 m/s, determine (a) the time when the velocity is zero, (b) the velocity and the total distance traveled when t 5 11 s.
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Ответ:
Explanation:
It is given that,
The acceleration of a particle,
(negative as the particle is decelerating)
Initial distance, x₁ = 20 m
Initial time, t₁ = 4 s
New distance x₂ = 4 m
Velocity, v = 10 m/s
(A) Calculating initial distance using second equation of motion as :
u = 21 m/s
When velocity of the particle is zero, time taken is t (say). Using first equation of motion as :
t = 2.62 seconds
So, the velocity of the particle is zero at t = 2.62 seconds.
(B) Velocity at t = 11 s
v = 13 m/s
Total distance covered at t = 11 s. The overall path travelled by the particle during its entire journey is called total distance covered.
d = 132.48 m
So, the distance travelled by the particle at t = 11 seconds is 132.48 meters.
Ответ: