The air contained water that froze at 0 °C The change in internal energy of the water as it froze was 0.70 kJ The specific latent heat of fusion of water is 330 kJ/kg
Calculate the mass of ice produced.

The mass of the ice produced is approximately 0.00212 kg

Explanation:

The given parameters are;

The temperature at which the air changed from water to ice = 0°C

The internal energy change of the water as it froze = 0.7 kJ

The specific latent heat of fusion of water = 330 kJ/kg

Given that the change in internal energy causes the water to change state, from the principle of energy conservation, we have;

The latent heat of fusion = The change in internal energy of the water as it froze

∴ The latent heat of fusion  = 0.70 kJ

The formula for the latent heat of fusion, = Mass × The specific latent heat of fusion,

Therefore, for the water, we have;

0.7 kJ = m × 330 kJ/kg

m = 0.7 kJ/(330 kJ/kg) ≈ 0.00212 kg

The mass, m, of the ice produced ≈ 0.00212 kg.

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