Physics: The car has a constant deceleration of 4.20 m/s^2. if its initial velocity was 24.0 m/s, how long does it take to come to a stop? answer in s

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The car has a constant deceleration of 4.20 m/s^2. - id42022312736, clarissajimenez27

andrewmena05

02.01.2022

The time is 5.71 sec.

Explanation:

Given that,

Acceleration a= -4.20 m/s^2

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

$0 =24.0 +(-4.20)\times t$

$t = \dfrac{-24.0}{-4.20}$

$t=5.71\ sec$

Hence, The time is 5.71 sec.

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