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julianjacobg126
29.01.2021 •
Physics
The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of the cart are 14.0 ft/s at point A and 19.0 ft/s at point C. The cart takes 3.50 s to go from point A to point C, and the cart takes 1.40 s to go from point B to point C. What is the cart's speed at point B
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Ответ:
Explanation:
To solve this exercise we will use the kinematics relations in one dimension, let's start by looking for the acceleration between points A and C
v = v₀ + a t
a =![\frac{v - v_o}{t}](/tpl/images/1075/4399/729fc.png)
a =![\frac{19 - 14}{3.50}](/tpl/images/1075/4399/c66b2.png)
a = 1.43 m / s²
this acceleration is uniform throughout the path.
Let's find the velocity at point B
let's calculate
Ответ: