Physics: The combination of an applied force and a friction force produces a constant total torque of 36.0 n,m on a wheel rotating about a fixed axis. the applied force acts for 6.00 s. during this time the angular speed of the wheel increases from 0 to 10.0 rad/s. the applied force is then removed, and the wheel comes to rest in 60.0 s. find (a) the moment of inertia of the wheel, (b) the magnitude of the frictional torque, and (c) the total number of revolutions of the wheel.

The combination of an applied force and a friction

Ответ:

datboyjulio21

14.03.2022

Physics

Part a)

I = 21.6 kg m^2

Part b)

$\tau_f= -3.6 Nm$

Part c)

N = 52.5 rev

Explanation:

As we know that the net torque on the wheel is given as

$\tau = 36 Nm$

now we know that its angular speed changes from 0 to 10 rad/s in time interval of 6.00 s

so we have

$\alpha = \frac{10 - 0}{6} = \frac{5}{3} rad/s^2$

Part a)

We know that the relation between torque and angular acceleration is given as

$\tau = I\alpha$

$36 = I(\frac{5}{3})$

I = 21.6 kg m^2

Part b)

Now the angular speed will reduce to zero after removing external torque in t = 60 s

now we have

$\alpha = \frac{0 - 10}{60} = -\frac{1}{6}$

so frictional torque is given as

$\tau_f = I\alpha$

$\tau_f = (21.6)(-\frac{1}{6}) = -3.6 Nm$

Part c)

Number of revolutions are given by the equation

$N = \frac{0 + \omega}{4\pi}t_1 + \frac{\omega + 0}{4\pi}t_2$

$N = \frac{10}{4\pi}6 + \frac{10}{4\pi}60 = 52.5 rev$

0,0(0 оценок)

Ответ:

jay3676

19.03.2023

Physics

Look at your data. With three foods, Flock

✔ X

was the most successful over three generations.

With two foods (no fruit), Flock

✔ Y

was the most successful.

Explanation:

Just took the test...Hope this helps :P

0,0(0 оценок)

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question