The diagram below shows a 5.0-kilogram bucket of water being swung in a horizontal circle of 0.70-meter radius
at a constant speed of 2.0 meters per second.
5.0-kg Bucket
0.70 m
The magnitude of the centripetal force on the bucket of water is approximately
1) 5.7 N
2) 14 N
3) 29 N
4) 200 N
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Ответ:
The magnitude of the centripetal force on the bucket of water is approximately 29 N
Definition of centripetal forceCentripetal force is the force that acts to keep an object moving in a circular motion. It is expressed mathematically as:
F = mv² / r
With the above formula, we can obtain the centripetal force acting on the bucket.
How to determine centripetal force•Mass (m) = 5 Kg
•Radius (R) = 0.7 m
•Velocity (v) = 2 m/s
•Centripetal force (F) =?
F = mv² / r
F = (5 × 2²) / 0.7
F = (5 × 4) / 0.7
F = 20 / 0.7
F = 29 N
Learn more about centripetal force:
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Ответ:
F = 29 N
Explanation:
We have,
Mass of the bucket of water is 5 kg
Radius of a horizontal circle is 0.7 m
Speed of the circle is 2 m/s
It is required to find the magnitude of centripetal force on the bucket of water. The formula used to find the magnitude of centripetal force is given by :
or
F = 29 N
So, the centripetal force on the bucket of water is 29 N.
Ответ:
Explanation:
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