Physics: The drag on a pitched baseball can be surprisingly large. Suppose a 145 g baseball with a diameter of 7.4 cm has an initial speed of 40.2 m/s (90 mph). Drag coefficient for a pitched baseball equals 0.35. Part A: What is the magnitude of the ball s acceleration due to the drag force? Part B: If the ball had this same acceleration during its entire 18.4 m trajectory, what would its final speed be?

Protons and neutrons have almost the same mass, while the electron is approximately 2000 times lighter. Protons and electrons carry charges of equal magnitude, but opposite charge. Neutrons carry no charge because they are neutral....

The drag on a pitched baseball can be surprisingly

Ответ:

carcon2019

20.01.2022

Physics

Part A)Acceleration of the ball is 10.1 m/s/sPart B)the final speed of the ball is given as v_f = 35.3 m/s

Explanation:

Part a)

As we know that drag force is given as

$F = \frac{C_d \rho A v^2}{2}$

C_d = 0.35

$A = \frac{\pi d^2}{4}$

$A = \frac{\pi(0.074)^2}{4}$

$A = 4.3 \times 10^{-3} m^2$

v = 40.2 m/s

so we have

$F = \frac{0.35\times 1.2 (4.3 \times 10^{-3})(40.2)^2}{2}$

F = 1.46 N

So acceleration of the ball is

$a = \frac{F}{m}$

$a = \frac{1.46}{0.145}$

a = 10.1 m/s^2

Part B)

As per kinematics we know that

v_f^2 - v_i^2 = 2 a d

v_f^2 - 40.2^2 = 2(-10.1)(18.4)

v_f = 35.3 m/s

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