annette211pdd8v9
11.12.2019 •
Physics
The electric-power industry is interested in finding a way to store electric energy during times of low demand for use during peak-demand times. one way of achieving this goal is to use large inductors. part a what inductance l would be needed to store energy e=3.0kwh (kilowatt-hours) in a coil carrying current i=300a? view available hint(s) ll l = nothing h provide feedback
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Ответ:
fc=mv²/r; r= mv²/fc = (1200×20)/6000 = 4 meters.