The elevator of a large building is to raise a net mass of 600 kg at a constant speed of 12 m/s using an electric motor. What is the minimum power rating of the motor?
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Ответ:
Explanation:
Given that.
Mass=600kg
v=12m/s
Since it is moving up then gravity is acting on it
take g=9.8m/s²
Then,
Power=workdone/time
Work done=force ×distance
Power=force×distance/time
Then, velocity =distance/time
So,
Power=force ×velocity.
The force to raise the object up is the weight of the object
Force=weight=mass ×gravity
Power=mass×gravity ×velocity.
Power=600×9.8×12
Power, =70560watts
Power=70.56KW
Ответ: