Physics: The end point of a spring vibrates with a period of 2.1 seconds when a mass m is attached to it. when this mass is increased by 6.810×101 kg, the period is found to be 3.4 seconds. find the value of m.

The end point of a spring vibrates with a period - id4012990, gumbyseth1969p45qjl

AestheticRoses

11.01.2022

Mass attached to the spring is 41.95 kg

Explanation:

We have given time period of the spring T = 2.1 sec

Let the mass attached is m

And spring constant is k

We know that time period is given by

$T=2\pi \sqrt{\frac{m}{k}}$

$2.1=2\pi \sqrt{\frac{m}{k}}$ ---------eqn 1

Now if the mass is increased by 68.10 kg then time period become 3.4 sec

So $3.4=2\pi \sqrt{\frac{m+68.10}{k}}$ ------eqn 2

Now dividing eqn 1 by eqn 2

$\frac{2.1}{3.4}=\sqrt{\frac{m}{m+68.10}}$

$0.381=\frac{m}{m+68.10}$

m=41.95 kg

So mass attached to the spring is 41.95 kg

0,0(0 оценок)