Physics: The gravitational force exerted by an object is given by f 5 mg where f is the force in newtons, m is the mass in kilograms, and g is the acceleration due to gravity, 9.81 m/s². calculate the force exerted per unit of area by a column of mercury (density 5 13.59 g/cm³) that is 76.0 cm high. how high would a column of water (density 5 1.00 g/cm³) have to be to exert the same force?

The gravitational force exerted by an object is given

lilybrok04

08.01.2022

Part a)

$P = 1.013 \times 10^5 Pa$

Part b)

H = 10.3 m

Explanation:

As we know that force due to gravity is given as

F = mg

now for force per unit area is given as

$P = \frac{F}{A}$

$P = \frac{\rho Ah g}{A}$

$P = \rho g H$

so for mercury we will have

$P = (13.59 \times 10^3) (9.81)(0.76)$

$P = 1.013 \times 10^5 Pa$

Part b)

Now if water also apply same force per unit area

then we will have

$P = \rho g H$

$1.013 \times 10^5 = (1000) 9.81 H$

H = 10.3 m

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