The headlights of a car are 1.4 m apart. What is the maximum distance (in km) at which the eye can resolve these two headlights? Take the pupil diameter to be 0.30 cm. (Assume the average wavelength of visible light is 555 nm.)

8.976 seconds

Explanation:

Initial Velocity (u) = 0

Acceleration (a) = 1.20 m/s^2

Time taken (t) = 7s

Negative acceleration = -4.25 m/s^2

To calculate the total time taken :

Time taken during the first phase of movement = 7 seconds

Final Velocity attained (V) equals :

Using v = u + at

v = 0 + 1.20(7)

v = 0 + 8.4

v = 8.4m/s

Therefore, time taken to bring the car to a stop.

Here final Velocity (v) = 0 ;

Initial Velocity (u) = 8.4m/s

From v = u + at

0 = 8.4 + (-4.25)t

0 = 8.4 - 4.25t

4.25t = 8.4

t = 8.4 / 4.25

t = 1.976 seconds

Therefore, total time taken equals:

7s + 1.976s = 8.976seconds