Physics: The initial velocity of a 4.0-kg box is 11 m/s, due west. after the box slides 4.0 m horizontally, its speed is 1.5 m/s. determine the magnitude and the direction of the non-conservative force acting on the box as it slides.

The initial velocity of a 4.0-kg box is 11 m/s,

jaydenhoward

13.03.2022

F = - 59.375 N

Explanation:

GIVEN DATA:

Initial velocity = 11 m/s

final velocity = 1.5 m/s

let force be F

work done = mass* F = 4*F

we know that

Change in kinetic energy = work done

kinetic energy = $= \frac{1}{2}*m*(v_{2}^{2}-v_{1}^{2})$

kinetic energy = $= \frac{1}{2}*4*(1.5^{2}-11^{2})$ = -237.5 kg m/s2

-237.5 = 4*F

F = - 59.375 N

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