The kinetic friction coefficient between a cabinet and the floor is 0.3. Mass of the cabinet is 300kg. A man pushes the cabinet along the floor with a 1000N force. Find the acceleration of the cabinet. g
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Ответ:
Explanation:
Step one:
given data
mass m= 300kg
applied force F= 1000N
coefficient of friction μ= 0.3
Step two:
The net force Fn= applied force-friction force
Fn=F-F1
F1= limiting force
F1=μ*m*g
F1=0.3*300*9.81
F1=882.9N
the Net force= 1000-882.9
Fn=117.1N
Step three:
we know that
F=ma
Fnet=ma
a= Fnet/m
a=117.1/300
a=0.39m/s^2
Ответ:
density of substance= 5.0g/ml
Mass = 7.4g
Density = Mass/Volume
Volume = Mass/Density
Volume = 7.4/5
Volume = 1.48ml✅.