The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant times the density of the liquid, p = ghd. how high a column of methanol (d = 0.79 g/ml) would be supported by a pressure that supports a 713 mm column of mercury (d = 13.6 g/ml)?

Height, h = 12.27 m

Explanation:

The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant times the density of the liquid i.e.

P = d g h

Pressure, P = 713 mm column of mercury

Density, d = 0.79 g/ml = 790 kg/m³

We have to find how high a column of methanol would be supported by a pressure P. Let the height is h. So,

g = acceleration due to gravity 9.8 m/s²

We know that, 1 mm of mercury = 133.32 Pa

713 mm of mercury = 95058.9 Pa

h = 12.27 m

Hence, this is the required solution.

802.3kilo joules of energy represents 191.75 kilo calorie