StephenCurry34
31.03.2021 •
Physics
The spring constant for the spring in above Table is 20 N/m.
Calculate the work done in stretching the spring until the extension of the spring is
0.050m
Work done =J
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Ответ:
W=1/2*k*x^2
W=1/2*20*0.050^2
W=0.025J
Ответ:
Explanation:
In a frictionless system with no acceleration, the tension in the rope must be F along its entire length
FBD analysis of the lower pulley has two upward acting tension vectors F and one downward acting weight vector W
2F = W
F = W/2
FBD analysis of the upper pulley has one upward acting support vector T and three downward acting tension vectors F
T = 3F
T = 3(W/2)
T = 1.5W