KaylaMaria
31.07.2019 •
Physics
The springs of a 1000 kg car compress 5.5 mm when its 68 kg driver gets into the driver's seat. if the car goes over a bump, what will be the frequency of vibrations?
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Ответ:
F = mg = kx
68 * g = k * 0.0055m
k = 121287.273
2.Find the frequency f:
ω = 2πf = √k/m
f = √(k / m)/ 2π = 1.7
Ответ: