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Kencharlot
06.12.2019 •
Physics
The "steam" above a freshly made cup of instant coffee is really water vapor droplets condensing after evaporating from the hot coffee. what is the final temperature of 250 g of hot coffee initially at 90.0ºc if 2.00 g evaporates from it? the coffee is in a styrofoam cup, so other methods of heat transfer can be neglected. (answer in ºc)
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Ответ:
Explanation:
For this exercise we will use the calorimetry heat ratios, let's start with the heat lost by the evaporation of coffee, since it changes from liquid to vapor state
Q₁ = m L
Where m is the evaporated mass (m = 2.00 103-3kg) and L is 2.26 106 J / kg, where we use the latent heat of the water
Q₁ = 2.00 10⁻³ 2.26 10⁶
Q1 = 4.52 10³ J
Now the heat of coffee in the cup, which does not change state is
Q coffee = M
(
-
)
Since the only form of energy transfer is terminated, the heat transferred is equal to the evaporated heat
Qc = - Q₁
M ce (
-
) = - Q₁
The coffee dough left in the cup after evaporation is
M = 250 -2 = 248 g = 0.248 kg
Since coffee is essentially water, let's use the specific heat of water,
Let's calculate
Ответ:
it helps to measure temperature of body
it contracts on cooling and expands on heating which is suitable to use as
thermometric substance