The sudden conversion of water to water vapor causes a dramatic expansion that can rip apart shoes. water has density 1000 kg/m3 and requires 2256 kj/kg to be vaporized. if horizontal current lasts 2.14 ms and encounters water with resistivity 176 ω·m, length 13.2 cm, and vertical cross-sectional area 17.8 × 10-5 m2, what average current is required to vaporize the water?
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Ответ:
137.76 A
Explanation: Heat is generated in a material when current is passed through the conducting material, this process is known as Joule heating or Ohmic heating or resistive heating.
Joule's first law, also known as Joule-Lenz law states that the heating power generated by an electrical conductor is directly proportional to the resistance of the conductor and square of the current flowing through it.
Mathematically, we have:
where:
Q= heat generatedi= current flowing through the conductorR= resistance of the conductort= time for which the current flows in the conductorGIven data:
heat required for the vapourization of water into steam, L 2256To find:
The current required to vaporize the given water, i = ?Firstly, we calculate the amount of energy required by the given amount of water to vaporize.
We have the density and heat of vaporization per kg of water.
volume of water=![13.2\times 10^{-2}m \times 17.8 \times 10^{-5} m^{2}](/tpl/images/0343/5771/c0067.png)
Now, Mass of water![= density \times volume\\=1000 \times 2.3496 \times 10^{-5}](/tpl/images/0343/5771/54c65.png)
∴Total amount of heat energy required,
we know, resistance![R= \frac{\rho.l}{A}](/tpl/images/0343/5771/0464f.png)
Putting the given values
Using eq. (1)
Ответ: