The triceps muscle in the back of the upper arm is primarily used to extend the forearm. suppose this muscle in a professional boxer exerts a force of 1.75 × 103 n with an effective perpendicular lever arm of 3.05 cm, producing an angular acceleration of the forearm of 115 rad/s2. what is the moment of inertia of the forearm, in kilogram meters squared?
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Ответ:
To solve this problem it is necessary to apply the concepts related to Torque as a function of the Force and the distance radius where it is applied.
By definition the Torque can be expressed as
Where
F = Force exerted
r = Radius
Substituting we have to
Through the second definition of the rotational Torque we can then find the moment of inertia for which we have to
Where
I = Moment of inertia
Replacing
Therefore the moment of inertia is
Ответ: