Physics: The velocity of a car traveling in a straight line increases from 0 meters/second to 30meters/second in 8 seconds. what is the average acceleration of the car?

The Force is DoubledExplanation:From Coulomb s Law the force is given asAs we have given that charge are doubled on one plate then the force will be:So the Force is Doubled If the charges are doubled on both plate then the force will be:So the Force is Quadrupled...

The velocity of a car traveling in a straight line

Ответ:

nxusasmangaliso7596

26.05.2020

Physics

The equation you need to know in order to solve this problem is v=v0+at, where v is final velocity, v0 is initial velocity, a is acceleration, and t is time. Plug in and solve:

30=0+a(8)

30=8a

*Divide both sides by 8*

a=3/75m/s^2

Hope this helps!!

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Ответ:

julie8669

31.07.2021

Physics

The Force is Doubled

Explanation:

From Coulomb's Law the force is given as

$Force=k\frac{q_{1}q_{2} }{r^{2} }$

As we have given that charge are doubled on one plate then the force will be:

$Force=k\frac{q_{1}q_{2} }{r^{2} }\\if\\ q_{1}=2q_{1}\\then\\Force=k\frac{2q_{1}q_{2} }{r^{2} }\\So\\Force=2(k\frac{q_{1}q_{2} }{r^{2} })\\Force=2*(Force)$

So the Force is Doubled

If the charges are doubled on both plate then the force will be:

$Force=k\frac{q_{1}q_{2} }{r^{2} }\\as\\ q_{1}=2q_{1}\\and\\q_{2}=2q_{2}\\then\\Force=k\frac{2q_{1}2q_{2} }{r^{2} }\\So\\Force=4(k\frac{q_{1}q_{2} }{r^{2} })\\Force=4*(Force)$

So the Force is Quadrupled

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The velocity of a car traveling in a straight line increases from 0 meters/second to 30meters/second in 8 seconds. what is the average acceleration of the car?

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