Physics: Two astronauts on opposite ends of a spaceship are comparing lunches. one has an apple, the other has an orange. they decide to trade. atronaut 1 tosses the 0.125 kg apple toward astronaut 2 with a speed of vi1=1.13 m/s. the 0.160 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.18 m/s. unfortunately, the fruits collide, sending the orange off with a speed of 0.999 m/s in the negative y direction. a) what are the final speed of the apple in this case (vf1)? b) what are the direction

the answer would be AExplanation:...

Two astronauts on opposite ends of a spaceship

SkinnestXOXO

08.01.2022

Explanation:

Mass of Apple, $m_a=0.125\ kg$

Mass of orange, $m_o=0.16\ kg$

Initial speed of orange, u_o=1.18i

Initial speed of Apple, u_a=-1.13i

Final speed of the orange, v_o=-0.999j

(a) Let v_a is the final sped of the apple. It can be calculated using the law of conservation of momentum as :

m_au_a+m_ou_o=m_av_a+m_ov_o

m_av_a=(m_au_a+m_ou_o)-m_ov_o

$m_av_a=(0.125\times (-1.13i)+0.16\times (1.18i))-0.16\times (-0.999j)$

m_av_a=(-0.141i+0.1888i)+0.159j

m_av_a=0.0478i+0.159j

$v_a=\dfrac{0.0478i+0.159j}{0.125}$

v_a=0.382i+1.27j

$|v_a|=\sqrt{0.382^2+1.27^2}=1.32\ m/s$

So, the final speed of the apple is 1.32 m/s

(b) The direction of the apple in this case is given by:

$tan\theta=\dfrac{1.27}{0.382}$

$\theta=73.25^{\circ}$

Hence, this is the required solution.

0,0(0 оценок)