Two cars pass each other traveling at the same speed. one car has a constant velocity of 15.0 m/s, east. the other car has a constant acceleration of 1.00 m/s , west. how much time will have elapsed until the cars are 164 m apart?
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Ответ:
The formula for calculating the distance at constant velocity is:
d = v * t
d = 15 t
The formula for distance at constant acceleration is:
d = v0 t + 0.5 a t^2
d = 15 t + 0.5 t^2
So after a sum distance of 164 m:
15 t + (15 t + 0.5 t^2) = 164
30 t + 0.5 t^2 = 164
t^2 + 60 t = 328
(t + 30)^2 = 328 + 30^2
t + 30 = ± 35.04
t = -65.04, 5.04
Since time cannot be negative, so the two cars are 164 m apart after about 5 seconds
Ответ:
15 N
Explanation:
The magnetic force on a piece of current-carrying wire is given by:
where
I is the current in the wire
L is the length of the piece of wire
B is the magnetic field strength
In this problem:
I = 10 A
B = 0.3 T
L = 5 m
Substituting into the equation, we find