Physics: Two long parallel wires are separated by 15 cm. one of the wires carries a current of 34 a and the other carries a current of 69 a. the permeabilty of free space is 1.257 × 10−6 n · m/a. determine the magnitude of the magnetic force on a 5.9 m length of the wire carrying the greater current. answer in units of mn

You throw it in ur mouth just like a ima stop right there Mark as brainliest again...

Two long parallel wires are separated by 15 cm.

coronadenise

11.03.2022

F = 0.018 N

Explanation:

Magnetic force between two parallel current carrying wires is given by

$F = \frac{\mu_0 i_1 i_2 L}{2\pi d}$

here we know that

i_1 = 34 A

i_2 = 69 A

d = 15 cm

L = 5.9 m

now from above formula we can say

$F = \frac{(4\pi \times 10^{-7})(34 A)(69 A)5.9}{2\pi (0.15)}$

now the force between two wires is given as

F = 0.018 N

0,0(0 оценок)