richellemjordan
14.05.2021 •
Physics
Two particles, with charges of 20.0 nC and -20.0 nC, are fixed at points with coordinates <0, 4.00 cm> and <0, -4.00 cm>. A particle with charge 10.0 nC is fixed at the origin. (a) Find the electric potential energy of the configuration of the three fixed charges. (b) A fourth particle, with a mass of 2.00 x 10-13 kg and charge of 40.0 nC, is released from rest at the point <3.00 cm, 0>. Find its speed after it has moved freely to a very large distance away.
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Ответ:
Explanation:
Potential energy of the system of charges
= 9 x 10⁹ x [ q₁q₂ / r₁₂ + q₂q₃ / r₂₃ + q₁q₃ / r₁₃ ]
here r₁₂ , r₂₃ , r₁₃ are distance between 1 st and 2 nd charge , 2 nd and 3 rd charge and fist and third charge.
r₁₂ = 8 cm , r₂₃ = 4 cm , r₁₃ = 4 cm.
q₁ = 20 x 10⁻⁹ C , q₂ = - 20 x 10⁻⁹ C , q₃ = 10 x 10⁻⁹ C
Potential energy = 9 x 10⁹ x [ - 400 x 10⁻¹⁸ / .08 + -200x10⁻¹⁸ / .04 + 200 x 10¹⁸ / .04 ]
= 9 x 10⁹ x - 400 x 10⁻¹⁸ / .08
= 45 x 10⁻⁶ J .
b)
Potential at the point of fourth charge due to three charges of 20 nC , - 20 nC and 10 nC at the centre
9 x 10⁹ [ 20 x 10⁻⁹ / .05 + - 20 x 10⁻⁹ / .05 + 10 x 10⁻⁹ / .03 ]
= 9 x 10⁹ x 10 x 10⁻⁹ / .03
= 3000 V .
potential energy of fourth particle = charge x potential
= 3000 x 40 x 10⁻⁹ = 12 x 10⁻⁵ J .
kinetic energy at infinity = 12 x 10⁻⁵ J
1/2 m v² = 12 x 10⁻⁵ J
.5 x 2 x 10⁻¹³ x v² = 12 x 10⁻⁵
v² = 12 x 10⁸
v = 3.46 x 10⁴ m/s
= 9 x 10⁹
Ответ:
m packs = 1.09*m = 1.09m
1 composition book = $2.79
n composition books = 2.79*n = 2.79n
Total cost = (1.09m + 2.79n)
Since there is a discount of 5%, the net price would be: 100% - 5% = 95%
Net Cost = 0.95*(1.09m + 2.79n)
Cindy's bill = $ 0.95*(1.09m + 2.79n)