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Lauraemia43
14.07.2019 •
Physics
Use the formulae for the lorentz transformation of z and t we derived in class to prove by explicit calculation that (tc)2-2 does not change under lorentz transformation. (10 pts)
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Ответ:
x₂ = 4.455 m
Explanation:
The average speed is defined as the displacement traveled between the time interval
v_average =![\frac{\Delta x}{\Delta t}](/tpl/images/1113/9301/f5272.png)
in this case we have a first stop walking west at speed v = 3.10 m / s a distance of x = 5.96 km = 5.96 10³ m
Let's find the time it takes on this tour
v = x / t
t = x / v
t₁ = 5.96 10³ / 3.10
t₁ = 1.9226 10³ s
in a second to walk east at a speed of v₂ = 0.744 m / s
v₂ = x₂ / t₂
t₂ = x₂ / v₂
for full movement
let's assume that the eastward movement is positive
v =![\frac{- x_1 + x_2}{t_1 +t_2}](/tpl/images/1113/9301/f4211.png)
v =![\frac{-x_1 +x_2}{t_1 + \frac{x_2}{t_2} }](/tpl/images/1113/9301/2e4d4.png)
the only unknown term is the distance to the east. We replace and resolve
1.19 =![\frac{-5.96 \ 10^3 + x_2}{1.92 \ 10^3 + \frac{x_2}{0.744} }](/tpl/images/1113/9301/52905.png)
1.19 (1.92 10³ +
) = x₂ 1.92 10³ - 5.96 10³
2.2848 10³ + 1.599 x₂ = 1.92 10³ x₂ - 5.96 10³
x₂ (1.92 10³ - 1.599) = 2.2848 10³ + 5.96 10³
x₂ = 8.5448 10³ / 1.918 10³
x₂ = 4.455 m