ashmarie69
30.07.2021 •
Physics
Vật nhỏ khối lượng 2 kg thả rơi tự do từ độ cao 50 m so với mặt đất. Lấy g = 10 m/s2. Động năng của vật sau khi vật rơi được 2 giây
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Ответ:
m=12kg
a=4m/s2
formula: F=m*a
F=12*4
F=48N