Weight = mass(m) x acceleration due to gravity(g) (Fw = mg.) g = 9.8 m/s2 on earth If someone weighs 711 N on Earth, what is that person's mass?
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Ответ:
The amount of gas that is to be released in the first second in other to attain an acceleration of 27.0 m/s2 is
Explanation:
From the question we are told that
The mass of the rocket is m = 6300 kg
The velocity at gas is being ejected is u = 2000 m/s
The initial acceleration desired is![a = 27.0 \ m/s](/tpl/images/0863/3532/4ddfb.png)
The time taken for the gas to be ejected is t = 1 s
Generally this desired acceleration is mathematically represented as
Here
is the rate at which gas is being ejected with respect to time
Substituting values
=>![170100 -27* \frac{\Delta m}{\Delta t} = 2000 * \frac{\Delta m}{\Delta t}](/tpl/images/0863/3532/091ea.png)
=>![170100 = 2027 * \frac{\Delta m}{\Delta t}](/tpl/images/0863/3532/a6cc7.png)
=>![\frac{\Delta m}{\Delta t} = \frac{170100}{2027}](/tpl/images/0863/3532/b1a43.png)
=>![\frac{\Delta m}{\Delta t} = 83.92 \ Kg/s](/tpl/images/0863/3532/b6aaf.png)