Wet sugar that contains 20 wt-% water is sent through a dryer in which 75 % of the water is removed. (a.) Taking a basis of 100 kg feed, calculate the mass fraction of sugar in the product that leaves the dryer. (b.) Calculate the ratio (kg removed/kg wet sugar leaving the dryer)

The mass fraction of sugar that leaves the dryer is 94%wt.

Explanation:

If the sugar contains 20%wt of water, for every 100kg of feed we have 80 kg of sugar and 20 kg of water.

The dryer will remove 75% of the water present in the feed. This equals to:

W_removed=0.75*0.20*100=15 kg of water.

Then, the output is 80 kg of sugar with 5 kg of water. That adds a total of 85 kgs.

Then, the mass fraction of sugar that leaves the dryer is:

m_s=80/85=0.94

The mass fraction of sugar that leaves the dryer is 94%wt.

C) It must be a different kind of atom.

Explanation:

In the reactor, some of the Uranium atoms break

When Uranium breaks it undergoes beta decay to finally produce Plutonium atom at the end.Plutonium has different atomic number than Plutonium.

Uranium isotope 238 absorbs a neutron to form Uranium -239.

This further emits beta particle and produces Neptunium-239

which again emits a beta particle and produces Plutonium atom.

Thus, plutonium atom is a different kind of atom. One atom is different from another atom by the number of protons in its nucleus.