What are the procedures use in bifilar suspension experiment​

In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state.

The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice.

1 kg = 1000g

40kg x (1000g/1kg) = 40,000g

Joules needed to melt the ice = 333.55 J/g x 40000 g = 13342000 J or

1.3342 x 107 J

Explanation:

Instead of 40kg input 50kg and get the answer