What is ke if mass = 5kg and velocity= 15m/s

1/2*m*v

=1/2*5*15^2

=0.5*5*225

=562.5 joule

b. 0.67

Explanation:

UCL = 1 + 0.10

        = 1.10 inch

LCL = 1 - 0.10

       = 0.9 inch

standard deviation = 0.005 inch

mean = 1 inch

Cpk

= min[(UCL - mean)/(3*standard deviation) , (mean - LCL)/(3*standard deviation))]

= min[(1.10 - 1)/(3*0.05) , (1 - 0.9)/(3*0.05))]

= min[0.67 , 0.67]

= 0.67

Therefore, Theprocess capability index (Cpk) if the long-run process mean is 1 inch is 0.67