What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.4 T?
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Ответ:
The acceleration of the proton is 8.714 x 10⁸ m/s².
Explanation:
Given;
speed of the proton, v = 6.5 m/s
magnetic field strength, B = 1.4 T
The magnetic force on the proton is given as;
F = qvB
The force of the moving proton is given as;
F = ma
Thus, ma = qvB
where;
m is mass of proton = 1.673 x 10⁻²⁷ kg
q is charge of proton = 1.602 x 10⁻¹⁹ J
a is the acceleration of the proton
Therefore, the acceleration of the proton is 8.714 x 10⁸ m/s².
Ответ: