What is the density (in kg/m3) of a woman who floats in freshwater with 4.92% of her volume above the surface
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Ответ:
The density of the woman is 950.8 kg/m³
Explanation:
Given;
fraction of the woman's volume above the surface = 4.92%
then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%
the specific gravity of the woman![= \frac{95.08}{100 } = 0.9508](/tpl/images/0999/2686/1b854.png)
The density of the woman is calculate as;
Density of fresh water = 1000 kg/m³
Density of the woman = 0.9508 x 1000 kg/m³
Density of the woman = 950.8 kg/m³
Therefore, the density of the woman is 950.8 kg/m³
Ответ:
they are not coming so I answered it
Explanation: