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giselaarcides
15.07.2020 •
Physics
What is the force of gravity (from the Earth) on the 700kg satellite if it’s 10km above the Earth's surface?
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Ответ:
g = 4.7 ×
m/![s^{2}](/tpl/images/0706/6652/c60b2.png)
Explanation:
Given that the mass of the satellite = 700 kg, and 10,000 m above the earth;s surface.
From Newton's second law,
F = mg ............... 1
From Newton's gravitation law,
F =
.................. 2
Where: F is the force, G is the gravitational constant, M is the mass of the first body, m is the mass of the second body, g is the gravitational force and r is the distance between the centers of the two bodies.
Equate 1 and 2 to have,
mg =![\frac{GMm}{r^{2} }](/tpl/images/0706/6652/f322b.png)
⇒ g =![\frac{GM}{r^{2} }](/tpl/images/0706/6652/b450b.png)
But; G = 6.67 ×
N
, M = 700 Kg, r = 10000 m
Thus,
g =![\frac{6.67*10^{-11*700} }{10000^{2} }](/tpl/images/0706/6652/71d7b.png)
=![\frac{4.669*10^{-8} }{1*10^{8} }](/tpl/images/0706/6652/aa3a8.png)
= 4.669 ×
m/![s^{2}](/tpl/images/0706/6652/c60b2.png)
The force of gravity on the satellite is 4.7 ×
m/
.
Ответ:
Speed is related to kinetic energy because kinetic energy is the energy of motion.
Hope this helped!