What is the kinetic energy of a 1800 kg car traveling at a speed of 30 m/s (≈65 mph)?

We have: K.E. = mv²/2
Here, m = 1800 Kg
v = 30 m/s

Substitute their values in the formula, 
K.E. =( 1800 × 30² )/ 2
K.E. = 1800 × 900 / 2
K.E. = 810000 / 2
K.E. = 4,05,000 J or 405 KJ

In short, your final answer would be 4.05 ×10⁵ Joules or 405 Kilo joules.

Hope this helps!

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