Physics: What is the magnitude of the electric force between two electrons separated by a distance of 0.14 nm (approximately the diameter of an atom)

Hello,The answer to this problem is oxygen Explanation:...

What is the magnitude of the electric force between

yanmanuel2215

02.01.2022

$F = 1.174*10^{-8} N$

Explanation:

Conceptual analysis:

To solve this problem we apply Coulomb's law:

Two point charges (q1, q2) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:

$F = \frac{k*q_{1}*q_{2}}{r^2}$ Formula (1)

$K=8.99*10^9 \frac{N*m^2}{C^2}$ : Coulomb constant

q1, q2 = charge in Coulombs (C)

Known information :

r = 0.14 nm

$1 nm = 10^{-9} m$

$r=0.14*10^{-9} m$

$q_{1} = -1,6*10^{-19} C$

$q_{2} = -1,6*10^{-19} C$

Development of the problem :

Replacing the information known in formula (1):

$F = \frac{8.99*10^9*1,6*10^{-19}*1,6*10^{-19}}{(0.14*10^{-9})^2}$

$F = 1.174*10^{-8} N$

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