Physics: What is the SI unit for the strength of the magnetic field? What is the SI unit for the strength of the magnetic field? Gauss Henry Tesla Becquerel Bohr magneton

Option D: Closer to the moon than to Earth because Earth has greater mass than the moon.We know that the gravitation force is directly proportional to the masses of two bodies and inversely proportional to the distance (r) between them. G is the gravitational constant. We know that mass of Earth is greater than the mass of moon . It means, the point where gravitational force would be equally acting would be closer to the moon. Let the mass of the earth be , mass of the spacecraft be and mass of...

What is the SI unit for the strength of the magnetic

Ответ:

gamallopatty

19.01.2022

Physics

Tesla

Explanation:

The SI unit of magnetic flux density or in other words strength of the magnetic field is Tesla (T).

Gauss (G) is the CGS unit of magnetic flux density. 1T=10^4G

Henry (H) is the SI unit of electrical inductance.

Becquerel (Bq) is the SI unit of radioactivity. 1 Bq is the activity of a radioactive material in which 1 nucleus decay in 1 second.

Bohr magneton is a physical constant used to measure the magnetic moment of an electron. In SI units:

$\mu_B=\frac{e\hbar}{2m_e}$

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Ответ:

amunnik04

13.12.2022

Physics

Option D: Closer to the moon than to Earth because Earth has greater mass than the moon.

We know that the gravitation force is directly proportional to the masses m_1, m_2 of two bodies and inversely proportional to the distance (r) between them.

$F=G\frac{m_1m_2}{r^2}$

G is the gravitational constant.

We know that mass of Earth $(5.97 \times 10^24 kg)$ is greater than the mass of moon $(7.34 \times 10^22 kg)$ . It means, the point where gravitational force would be equally acting would be closer to the moon.

Let the mass of the earth be m_1 , mass of the spacecraft be m_2 and mass of moon be m_3 , $r_{12}$ is the distance between earth and spacecraft and $r_{32}$ is the distance between moon and spacecraft.

Let the force acting on spacecraft due to Earth be:

$F_1=G\frac{m_1m_2}{r_{12}^2}$

Let the force acting on spacecraft due to moon be:

$F_2=G\frac{m_3m_2}{r_{32}^2}$

For forces to be equal,

F_1=F_2

$G\frac{m_1m_2}{r_{12}^2}=G\frac{m_3m_2}{r_{32}^2}$

$\Rightarrow \frac{m_1m_2}{r_{12}^2}=\frac{m_3m_2}{r_{32}^2} \Rightarrow \sqrt {\frac{m_1}{m_3}}=\frac{r_{12}}{r_{32}}$

$m_1 m_3 \Rightarrow r_{12}r_{32}$

This means that the distance of the spacecraft from the Earth would be larger than the distance from the moon where the gravitational force would be equally acting by Earth and Moon.

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What is the SI unit for the strength of the magnetic field? What is the SI unit for the strength of the magnetic field? Gauss Henry Tesla Becquerel Bohr magneton

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