What provides the centripetal force needed to keep Earth in orbit?
A. inertia
B. its rotation on its axis
C. the gravitational pull of the Sun
D. the gravitational pull of the Moon
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Ответ:
option C
Ответ:
Vertical: a=-9.81m/s^2
v=-9.81t + 20sin(n). Where n is the angle
So vertical position is the integral of velocity
s=-9.81/2 t^2 +20t sin(n)
s=-4.905t^2+20t sin(n)=0
This can help us find n in terms of t. We need t such that the arrow traveling at 20m/s makes it exactly 30m. Using the formula s=vt
30=20t cos(n)
t=1.5/cos(n)
Putting this in our previous equation
-4.905(1.5/cos(n))^2+
20(1.5/cos(n))sin(n)=0
Now multiply both sides by (cos(n))^2 to get
-4.905(1.5)+20(1.5)cos(n)sin(n)=0
Or
-7.36+30sin(2n)=0
Now find n
7.36= 30sin(2n)
7.36/30=sin(2n)
2n=arcsin(7.36/30)
2n=14.2
n=7.1 degrees