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21.10.2020 •
Physics
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting, the current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V. When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V.
A. Find the battery's EMF.
B. What is its internal resistance?
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Ответ:
EMF = 11.35 V
R = 0.031Ω
Explanation:
To find the battery's EMF and the internal resistance we need to use Ohm's law:
Where:
V: is the voltage
I: is the current
R is the resistance
We have:
The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:
(1)
When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:
(2)
By solving equation (1) and (2) for R we have:
Hence, the internal resistance is 0.031 Ω.
Now, by entering R into equation (1) we can find the battery's EMF:
Therefore, the battery's EMF is 11.35 V.
I hope it helps you!
Ответ:
Explanation:
Heating a substance causes molecules to speed up and spread slightly further apart, occupying a larger volume that results in a decrease in density. ... Hot water is less dense and will float on room-temperature water. Cold water is more dense and will sink in room-temperature water.