Physics: When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is 9.90 cm wide on a screen that is 2.53 m away. how wide is the slit?

When violet light of wavelength 415 nm falls

Ответ:

GabbyGood1072

14.03.2022

In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
$y_n= \frac{n \lambda D}{a}$ (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
$\lambda$ is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
The width of the first peak (let's call it $\Delta y$ ) corresponds to twice the distance of the first minimum:
$\Delta y = 2 y_1=9.90 cm=0.099 m$
which means
$y_1 = \frac{\Delta y}{2}= \frac{0.099 m}{2}=0.0495 m$

The wavelength of the light in the problem is
$\lambda=415 nm=4.15 \cdot 10^{-7} m$
and the distance of the screen from the slit is
D=2.53 m

So by using these data and re-arranging the equation, we can find the width of the slit:
$a= \frac{1 \lambda D}{y_1} = \frac{(1)(4.15 \cdot 10^{-7} m)(2.53 m)}{0.0495 m}=2.15 \cdot 10^{-5} m = 0.0215 mm$

0,0(0 оценок)

Ответ:

9444

09.09.2021

Physics

Though he largely pursued a policy of peaceful coexistence with the West, the Cuban Missile Crisis began after he positioned nuclear weapons 90 miles from Florida.

Explanation:

0,0(0 оценок)

When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is 9.90 cm wide on a screen that is 2.53 m away. how wide is the slit?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question