Which graph represents the relationship between the magnitude of the gravitational force exerted by earth on a spacecraft the distance between the center of the spacecraft the center of earth

B as distance increase force decrease, but it is not a linear relationship.

We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The coordinate origin is at the release point (the initial position for the ball as it begins projectile motion in the sense of §4-5), and we let θ

0

be the angle of throw (shown in the figure). Since the horizontal component of the velocity of the ball is v

x

=v

0

cos40.0°, the time it takes for the ball to hit the wall is

t=

v

x

Δx

=

(25.0m/s)cos40.0

o

22.0m

=1.15s.

(a) The vertical distance is

Δy=(v

0

sinθ

0

)t−

2

1

gt

2

=(25.0m/s)sin40.0

o

(1.15s)−

2

1

(9.80m/s

2

)(1.15s)

2

=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: v

x

=v

0

cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

v

y

=v

0

sinθ

0

−gt=(25.0m/s)sin40.0

o

−(9.80m/s

2

)(1.15s)=4.80m/s.

(d) Since v

y

>0 when the ball hits the wall, it has not reached the highest point yet.