![jvontaemyles14](/avatars/24107.jpg)
jvontaemyles14
07.11.2020 •
Physics
Which has a higher viscosity orange juice or chocolate syrup
Solved
Show answers
More tips
- H Health and Medicine Why Do Humans Have One Heart?...
- S Style and Beauty How to knit a hooded cowl?...
- H Horoscopes, Magic, Divination How to Cast a Love Spell on a Guy? Guide for Guys...
- S Style and Beauty Tricks and Tips: How to Get Rid of Freckles...
- H Health and Medicine What is Autism? Understanding the Basics of This Neurodevelopmental Disorder...
- F Family and Home How to Properly Use a Water Level?...
- D Dating, Love, Relationships 10 Useful Tips on How to Survive a Breakup?...
- F Food and Cooking Apple Cider Vinegar: The Ultimate Health and Beauty Solution...
- C Computers and Internet Е-head: How it Simplifies Life for Users?...
Answers on questions: Physics
- P Physics Convection occurs mainly in...
- P Physics In which situation would an object weigh the least? (assume all the objects have the same mass) a) an object on earth eliminate b) an object on the moon c) an object half-way between...
- H History 10D 1 2 How can we learn from the Silk Road today?...
- H History Please can someone help! Find out at least 10 facts about the Battle of Stalingrad and write them out in your own words. What were the turning points in the battle and why was it...
- H History At what point did dutch financiers come through with monetary assistance?...
- M Mathematics Benn Cornell and Tom Ingulli drove to Chicago a distance of 510 miles, their car gets 23 miles per gallon of gasoline. gasoline costs them $2.59 per gallon. how much did they spend...
Ответ:
Vf₁ = 30 m/s
s₂ = 90 m
car wins the race.
Explanation:
To find the speed of car after 5 s, we use 1st equation of motion:
Vf₁ = Vi₁ + a₁t₁
where,
Vf₁ = Final Speed of Car = ?
Vi₁ = Initial Speed of Car = 0 m/s
a₁ = acceleration of car = 5 m/s²
t₁ = time = 5 s
Therefore,
Vf₁ = 0 m/s + (5 m/s²)(5 s)
Vf₁ = 25 m/s
To find the distance of motorcycle after 6 s, we use 2nd equation of motion:
s₂ = Vi₂ t₂ + (1/2)a₂t₂²
where,
s₂ = distance covered by the motorcycle = ?
Vi₁ = Initial Speed of motorcycle = 0 m/s
a₂ = acceleration of motorcycle = 8 m/s²
t₂ = time = 6 s
Therefore,
s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²
s₂ = 90 m
We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:
For Car:
s₁ = Vi₁ t₁ + (1/2)a₁t₁²
where,
s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)
Therefore.
150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²
t₁ = √60 s²
t₁ = 7.74 s
For Motorcycle:
s₂ = Vi₂ t₂ + (1/2)a₂t₂²
where,
s₁ = 200 m
Therefore.
200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²
t₂ = √80 s²
t₂ = 8.94 s
Since, the car takes less time to reach finish line.
Therefore, car wins the race.