X-rays of wavelength 0.13 nm fall on a microcrystalline powder sample. the sample is located 17 cm from the photographic film. the crystal structure of the sample has an atomic spacing of 0.22 nm. calculate the radii of the diffraction rings corresponding to first-and-second-order scattering. note in the figure 35-28 in the textbook that the x-ray beam is deflected through an angle 2pi. express your answer using two significant figures. enter your answers numerically separated by a comma.

The increase internal energy is 1,760.41 J

Explanation:

The given parameters of the worker, sledgehammer, and rail line are;

The mass of the spike driven into the rail, m₁ = 0.500 kg

The mass of the sledgehammer, m₂ = 2.50 kg

The speed of the sledgehammer, v = 65.0 m/s

The fraction of the hammers kinetic energy, KE, converted to the internal energy of the hammer and the spike, Δ = 1/3 × KE

Therefore, we have;

The kinetic energy, KE, of the sledgehammer is given by KE = 1/2·m₂·v²

Where;

m₂ = The mass of the sledge hammer = 65.0 m/s

v = The velocity o the sledgehammer

∴ KE = 1/2 × 2.50 kg × (65.0 m/s)² = 5,281.25 J

Therefore;

The increase internal energy, Δ = 1/3 × 5,281.25 J = 1760.41 J