Physics: You are 80 kg and you want to push over a player that is 100 kg with a force of 1200 n at 20 degrees above the horizontal. you both have a static friction coefficient of 0.95. if he is pushing back with 1200 n at 20 degrees below horizontal on you, will you accelerate backwards?

A - They are protein cells and are found in extracellular matrix of connective tissue and produced by muscle cells.I don t understand they are the same question tho...

You are 80 kg and you want to push over a player

Ответ:

joannakawata6

10.01.2022

Physics

I will not accelerate backwards.

Explanation:

Whenever we want to discuss the motion of a body,we need to consider the forces acting on that body and not the force it is exerting on other bodies.

Let be the force exerted by the other player on you.

Horizontal force exerted by other player is $FCos(\alpha )$ where $\alpha$ is the angle between the direction of force and horizontal.

Given,

$F=1200N\\\alpha =20^{0}$

So,the horizontal force is $F_{h}=1200\times Cos20=1127.63N$

Vertical force exerted is $F_{v}=1200\times Sin(20)=410.42N$

Normal reaction force from ground is the sum of vertical force and my weight= N=80(9.8)+410.42=1194.42N

Let the coefficient of static friction be $c_{s}$

given, $c_{s}=0.95$

Maximum frictional force is $f=N\times c_{s}=1194.42\times 0.95=1134.7N$

Since the maximum frictional force is greater than the horizontal force,I will not accelerate backwards.

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You are 80 kg and you want to push over a player that is 100 kg with a force of 1200 n at 20 degrees above the horizontal. you both have a static friction coefficient of 0.95. if he is pushing back with 1200 n at 20 degrees below horizontal on you, will you accelerate backwards?

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