You are driving through town at 19 m/s when suddenly a car backs out of a driveway in front of you. you apply the brakes and begin decelerating at 3.2 m/s2 . part a how much time does it take you to stop?

Time taken to stop = 5.94 seconds

Explanation:

We have equation of motion, v = u + at

Final velocity , v = 0 m/s

Initial velocity, u = 19 m/s

Acceleration, a = -3.2 m/s²

time, t = ?

Substituting

            0 = 19 - 3.2 x t

            t = 5.94 s

Time taken to stop = 5.94 seconds

The correct answer is
A)0 m

In fact, the displacement is a vectorial quantity that corresponds to the difference between the initial and the final position of an object in motion. In this problem, the final position of the ball is equal to its initial position (because the ball returns back to where it was launched), so the displacement of the ball is zero.