Physics: You are given a semiconductor resistor made from silicon with an impurity concentration of resistivity 1.00×10−3ωm. the resistor has a height of h =0.5 mm, a length of l = 2 mm, and a width of w = 1.25 mm. the resistor can absorb (dissipate) up to p = 7.81w. what is the resistance of the resistor (r), the maximum voltage (v), and the maximum current (i)?

You are given a semiconductor resistor made from

Ответ:

pookie879

12.03.2022

Physics

Resistance = $3.2 \Omega$ , Current = 1.56 A, Voltage =4.99 V

The resistance,

$R=\frac {\rho l}{A}$

where, $\rho$ is resistivity, A is the area and l is the length of the resistor.

It is given that:

$\rho=1.0\times10^{-3}\Omega m$

Length, l=2 mm

Area, $A= width \times height=1.25 mm\times 0.5 mm=0.625 mm^2$

Hence, $R=\frac{1.0\times10^{-3}\Omega m \times 2\times10^{-3}m}{0.625\times10^{-6}m^2}=3.2\Omega$

We know, Power, P=I^2R

$\Rightarrow I=\sqrt{\frac{P}{R}}$

P=7.81 W

$I=\sqrt{\frac {7.81 W}{3.2\Omega}}=\sqrt{2.44}A=1.56A$

We know, Voltage, $V=IR=1.56\times3.2=4.99 V$

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Ответ:

Zykuko

16.11.2020

Physics

Median

Explanation:

we commonly use mean as the measure of the center of the data.But Median is better measure than mean.

Extra information:-

Median formula:-

$\boxed{\begin{minipage}{6cm}$\bigstar$\:\:\sf Median = l + $\sf\dfrac{\frac{n}{2}-C.f.}{f}\times h\\\\Here: \\1)\:n = \sum f =\\2)\:l=Lower\:limit\:of\:median\:class=\\3)\:C.f.=Cumulative\:frequency\:of\:class\\preceeding\:the\:median\:class=\\4)\:f= frequency\:of\:median\:class=\\5)\:h= Class\:interval = \end{minipage}}$

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